Refrigeration COP and Compressor Power
Find the compressor input power and the heat rejected at the condenser for a cooling system with a 35 kW evaporator load and a COP of 3.5.
Mechanical, HVAC & Fluids · Last reviewed
Given
A refrigeration system absorbs 35 kW of heat at the evaporator. Its coefficient of performance, defined as cooling effect divided by compressor input power, is 3.5 at these conditions.
Find
The compressor input power, the heat rejected at the condenser, the cooling capacity in tons and the energy efficiency ratio (EER).
Solution
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Questions
Can COP be higher than 1?
Yes. COP compares heat moved with work input, and a cycle can move much more heat than the work it takes. That is not a perpetual-motion claim, because the heat is moved, not created.
How do COP and EER relate?
EER is COP expressed in Btu/h per watt, so EER = 3.412 × COP.
Does COP include the fans and pumps?
Only if the definition says so. State what is included whenever you quote a COP.
Educational material. Examples use simplified, hypothetical inputs and are not a design, a construction document or professional engineering advice. Confirm requirements with the codes and standards adopted where the work is built and with a licensed engineer.